(X+1)^2+2(x-2)=(x+1)(x-2)

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Solution for (X+1)^2+2(x-2)=(x+1)(x-2) equation: 



(X+1)^2+2(X-2)=(X+1)(X-2)

We move all terms to the left:

(X+1)^2+2(X-2)-((X+1)(X-2))=0

We multiply parentheses

(X+1)^2+2X-((X+1)(X-2))-4=0

We multiply parentheses ..

-((+X^2-2X+X-2))+(X+1)^2+2X-4=0



We calculate terms in parentheses: -((+X^2-2X+X-2)), so:

(+X^2-2X+X-2)

We get rid of parentheses

X^2-2X+X-2

We add all the numbers together, and all the variables

X^2-1X-2

Back to the equation:

-(X^2-1X-2)



We add all the numbers together, and all the variables

2X-(X^2-1X-2)+(X+1)^2-4=0

We get rid of parentheses

-X^2+2X+1X+(X+1)^2+2-4=0

We add all the numbers together, and all the variables

-1X^2+3X+(X+1)^2-2=0

We move all terms containing X to the left, all other terms to the right

-1X^2+3X+(X+1)^2=2

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